cho \(P\left(x\right)=x^4+ax^3+bx^2+d\)

có \(P\left(1\right)=5;P\left(2\right)=7;P\left(3\right)=9;P\left(4\right)=11\)

Ttính P(10);P(11);P(12)

Mọi người giải giúp mình câu này với, mình đang cần gấp T TTính bằng cách thuận tiện nhất 5 11 x 7 25 15 11 x 1 5

tTính

đ) 1/3:0,25+(1+1/6).4/7-60%

Thanks 

1. (x-6)^2 = 2(x-6) ||||| 2. 2(x-3)^2 = (x-3)(x+5) ||||| 3. 4(x-3)=2x-5(2x+3) | 4. x2 +4 -2 (x-1) = (x-2)^2 |||| 4. x-3/5 = 6 - 1-2x/3 ||||| 5. x+2 = 6-5x/2 ||||| 6. x+2/5 - x+3 = x-2/2 ||||| 7. 2x-5/x-4 = 2x+1/x+2 ||||| 8. X+3/x-3 - x-1/x+3 = x2 + 4x + 6/x2 -9 |||| 9. 3x-3/x2-9 -1/x-3 = x+1/x+3 |||| 10. X+1/x-1 - x-1/x+1 = 4/x2 -1

a) 3/10 x x=2/5         b) 1/8 : x - = 1/2        d) 5/6 : 3/4          1: 2/3

a) 5/6 + 3/4               1 + 2/3

b) 5/6 - 3/4               1 - 2/3

c) 5/6 x 3/4               1x 2/3

Bài 1 

a, Tính P=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+....+1/2012(1+2+3+...+2012)

b,Tìm x thỏa mãn 4^5+4^5+4^5+4^5/3^5+3^5+3^5.6^5+6^5+6^5+6^5+6^5+6^5/2^5+2^5=2^x

1) (3x-2)/3-2=(4x+1)/4
2) (x-3)/4+(2x-1)/3=(2-x)/6
3) 1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)
4) (x+4)/5-x+4=x/3-(x-2)/2
5) (4-5x)/6=2(-x+1)/2
6) (-(x-3))/2-2=5(x+2)/4
7)2(2x+1)/5-(6+x)/3=(5-4x)/15
8) (7-3x)/2-(5+x)/5=1
9)(x-1)/2+3(x+1)/8=(11-5x)/3
10)(3+5x)/5-3=(9x-3)/4

1)  (3x-2)/3-2=(4x+1)/42)  (x-3)/4+(2x-1)/3=(2-x)/63)  1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)4)  (x+4)/5-x+4=x/3-(x-2)/25)  (4-5x)/6=2(-x+1)/2 6)  (-(x-3))/2-2=5(x+2)/4 7)2(2x+1)/5-(6+x)/3=(5-4x)/158)  (7-3x)/2-(5+x)/5=1 9)(x-1)/2+3(x+1)/8=(11-5x)/310)(3+5x)/5-3=(9x-3)/4  

 

1. (x-6)^2 = 2(x-6) 

2. 2(x-3)^2 = (x-3)(x+5)

3. 4(x-3)=2x-5(2x+3)

4. x2 +4 -2 (x-1) = (x-2)^2

5. x-3/5 = 6 - 1-2x/3 

6. x+2 = 6-5x/2

7. x+2/5 - x+3 = x-2/2

8. 2x-5/x-4 = 2x+1/x+2

9. X+3/x-3 - x-1/x+3 = x2 + 4x + 6/x2 -9

10. 3x-3/x2-9 -1/x-3 = x+1/x+3 

11. X+1/x-1 - x-1/x+1 = 4/x2 -1